https://leetcode.cn/problems/reverse-linked-list
/** * Definition for singly-linked list. * function ListNode(val, next) { * this.val = (val===undefined ? 0 : val) * this.next = (next===undefined ? null : next) * } */ /** * @param {ListNode} head * @return {ListNode} */ var reverseList = function(head) { let prev = null; let cur = head; while (cur !== null) { let next = cur.next; cur.next = prev; prev = cur; cur = next; } return prev; };
原创文章,作者:czhdawn,如若转载,请注明出处:https://www.czhdawn.cn/archives/4938